有限数学示例

$[\begin{array}{c} 1 & 1 & 1 & 26 \\ 7000 & 14000 & 28000 & 434000 \end{array}]$

解题步骤 1

Perform the row operation $R_{2} = R_{2} - 7000 R_{1}$ to make the entry at $2, 1$ a $0$ .

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解题步骤 1.1

Perform the row operation $R_{2} = R_{2} - 7000 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 1 & 1 & 26 \\ 7000 - 7000 \cdot 1 & 14000 - 7000 \cdot 1 & 28000 - 7000 \cdot 1 & 434000 - 7000 \cdot 26 \end{array}]$

解题步骤 1.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & 1 & 1 & 26 \\ 0 & 7000 & 21000 & 252000 \end{array}]$

解题步骤 2

Multiply each element of $R_{2}$ by $\frac{1}{7000}$ to make the entry at $2, 2$ a $1$ .

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解题步骤 2.1

Multiply each element of $R_{2}$ by $\frac{1}{7000}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & 1 & 1 & 26 \\ \frac{0}{7000} & \frac{7000}{7000} & \frac{21000}{7000} & \frac{252000}{7000} \end{array}]$

解题步骤 2.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & 1 & 1 & 26 \\ 0 & 1 & 3 & 36 \end{array}]$

解题步骤 3

Perform the row operation $R_{1} = R_{1} - R_{2}$ to make the entry at $1, 2$ a $0$ .

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解题步骤 3.1

Perform the row operation $R_{1} = R_{1} - R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 - 0 & 1 - 1 & 1 - 3 & 26 - 36 \\ 0 & 1 & 3 & 36 \end{array}]$

解题步骤 3.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & 0 & - 2 & - 10 \\ 0 & 1 & 3 & 36 \end{array}]$

有限数学 示例